(5k^2-3k+4)+(3k-7)=

Solution for (5k^2-3k+4)+(3k-7)= equation:

Simplifying
(5k2 + -3k + 4) + (3k + -7) = 0

Reorder the terms:
(4 + -3k + 5k2) + (3k + -7) = 0

Remove parenthesis around (4 + -3k + 5k2)
4 + -3k + 5k2 + (3k + -7) = 0

Reorder the terms:
4 + -3k + 5k2 + (-7 + 3k) = 0

Remove parenthesis around (-7 + 3k)
4 + -3k + 5k2 + -7 + 3k = 0

Reorder the terms:
4 + -7 + -3k + 3k + 5k2 = 0

Combine like terms: 4 + -7 = -3
-3 + -3k + 3k + 5k2 = 0

Combine like terms: -3k + 3k = 0
-3 + 0 + 5k2 = 0
-3 + 5k2 = 0

Solving
-3 + 5k2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 5k2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 5k2 = 0 + 3
5k2 = 0 + 3

Combine like terms: 0 + 3 = 3
5k2 = 3

Divide each side by '5'.
k2 = 0.6

Simplifying
k2 = 0.6

Take the square root of each side:
k = {-0.774596669, 0.774596669}